f(x)=2x^3+2x^2-4x
The zeros of polynomial functions
2x^3 + 2x^2 - 4x = 0
2x(x^2 + x - 2) = 0
2x(x - 1)(x + 2) = 0
2x = 0; x = 0
x - 1 = 0; x = 1
x + 2 = 0; x = -2
Answer
x = -2 , 0 , 1
Point-slope form of a line: We need a point (x₀,y₀) and the slope "m";
y-y₀=m(x-x₀)
We have the next equation of line:
y=1/2 x-2 (slope-intercept form y=mx+b)
the slope of this line is 1/2 (m=1/2)
And any one point could be:
if x=0; then y=1/2 (0)-2=-2 (0,-2)
Therefore, we already have the point (0-,2) and the slope (m=1/2)
y-y₀=m(x-x₀)
y+2=1/2(x-0)
Answer: the point slope form of y=1/2 x-2; would be:
y+2=1/2(x-0)
Answer:
-40 °F = -40 °C
Step-by-step explanation:
(1) F = 1.8 C + 32
If the Fahrenheit and Celsius temperatures are the same, then
(2) F = C Substitute (2) into (1)
C = 1.8C + 32 Subtract 1.8 C from each side
C – 1.8 C = 32 Combine like terms
-0.8C = 32 Divide each side by -0.8
C = -32/0.8
(3) C = -40 Substitute (3) into (1)
F = 1.8(-40) + 32
F = -72 + 32
F = -40
So, -40 °F = -40 °C
The thermometer below shows that -40 °F = -40 °C.
I believe that answer is B. (The second one)
Hope this helped !!
