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Angelina_Jolie [31]
3 years ago
13

I need help:

Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

8 green tshirts

Step-by-step explanation:

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Which quadratic function in vertex form has a vertex at (−5 , −4) and passes through the point (−2 , −1)?
ioda

Answer:

y = 1/3(x + 5)^2 - 4

Step-by-step explanation:

The general vertex form is;

y = a(x-h)^2 + k

From the question, (h,k) are the coordinates of the vertex which is (-5,-4)

So we have

y = a(x + 5)^2 -4

So we need to get the leading coefficient

Simply substitute the point it passes through

x = -2 and y = -1

-1 = a(-2 + 5)^2 - 4

-1 = a(3)^2 -4

-1 = 9a -4

9a = 4-1

9a = 3

a = 3/9

a = 1/3

So the equation is;

y = 1/3(x + 5)^2 - 4

5 0
3 years ago
What is the cost price of 600 pens
Rufina [12.5K]

Answer:

600 *10=6000 if each of these are of 10

6 0
3 years ago
2. Mr. Walters starts preparing breakfast at
alexdok [17]
Answer: 55 minutes

Explanation:

Round 6:45 to 6:50.
From 6:50 it takes 1 hour/60 minutes to become 7:50.
Then subtract the 5 minutes we added when we rounded up to 6:50.
60-5=55 minutes
8 0
2 years ago
Read 2 more answers
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
How do i find BC?<br><br> Khan Academy
Brrunno [24]

Answer:

using cos=adjacent/hypotenuse

Step-by-step explanation:

in this case cos(60)=x/4√3

x=cos(60)*4√3

x=3.46

6 0
3 years ago
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