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2 years ago

Divide 33 photos into two groups so the ratio it 4 to 7

Mathematics

2 answers:

katrin2010 [14]2 years ago

8 0

4 to 7......add them = 11

4/11 * 33 = 132/11 = 12
7/11 * 33 = 231/11 = 21

SpyIntel [72]2 years ago

5 0

Cool I had the same question for homework tonight!

4+4+4=12
7+7+7=21

The answer is
12:21 or 12/21

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AT the local zoo, the aquarium can be seen from the Reptile Room and the Amphibian Arena. What is the total area of both rooms a

BartSMP [9]

Answer:

The total area of both rooms and the aquarium is equal to 10,932 ft²

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

the length sides of Aquarium are

(83-32) x (72-52)-----> 51 ft x 20 ft

Area reptile room=(83*72)-area of aquarium----> 83*72-51*20---> 4,956 ft²

[ total area of both rooms]=2*4,956-----> 9,912 ft²

I'm assuming that the two areas are equal

Area of aquarium=51*20=1,020 ft²

therefore

the total area of both rooms and the aquarium is equal to

9,912 ft²+1,020 ft²=10,932 ft²

6 0

2 years ago

What is 150% as a fraction

Helen [10]

150% as fraction is 150/100 = 15/10 = 3/2 and thats the simplest form :)))
i hope this is helpful
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6 0

2 years ago

Read 2 more answers

You deposit $3000 into a bank account that pays 1.25% annual interest, compounded semi-annually. What is the final balance after

mojhsa [17]

Answer:

$3,153.32

Step-by-step explanation:

Given that

The deposited amount is $3,000

The annual interest rate is 1.25%

So, the semi-annual interest rate is 1.25% ÷2 = 0.625%

And, the time period = 4 × 2 = 8

We need to find out the final balance

So,

As we know that

Future value = Present value × (1 + rate of interest)^number of years

= $3,000 × (1 + 0.625%)^8

= $3,153.32

8 0

2 years ago

What is 10.1x-1.6+44=-7

Annette [7]

Answer x=-9/2. It’s period is times?? I might wrong

5 0

2 years ago

An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2 : Suppose a sample of

rewona [7]

Answer:

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.

333 - 257 = 76 have spills.

This means that $n = 333, \pi = \frac{76}{333} = 0.228$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 - 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.199$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 + 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.257$

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

6 0

2 years ago