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noname [10]
2 years ago
8

What can you tell about the mean of each distribution?

Mathematics
2 answers:
Brrunno [24]2 years ago
7 0

Answer:

Step-by-step explanation:

help please

butalik [34]2 years ago
5 0

Answer: 23.71 less at new leash than average cost than no rug stuff

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SOMEONE PLEASE HELP.>>>>>>
alexira [117]

Answer:

The answer would be B



6 0
3 years ago
What is the missing numerator of 4/9= ?/81
yKpoI14uk [10]
To solve this question, first cross multiply
Let ? = x

4/9 = x/81

4(81) = 9(x)

Simplify.

81 x 4 = 324

324 = 9x

Isolate the x, divide 9 from both sides

324/9 = 9x/9

x = 324/9

x = 36


4/9 = 36/81

36 is your answer

hope this helps!
4 0
3 years ago
Read 2 more answers
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
PLEASE HELP ME 10 POINTS!!!!!
NemiM [27]
The answer to your question would be 150 (c)
6 0
3 years ago
Solve the equation.<br><br> 12a=11
USPshnik [31]
A= 11/12 i hope this helped !!!
5 0
2 years ago
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