Answer:
$511.5
Step-by-step explanation:
Given: Selling price of bike at Danny´s shop is $550
Bike is sold 7% less at competitor´s shop.
Lets find the discounted amount at Danny´s competitor shop.
∴ 
Now, finding the cost of bike at Danny´s competitor.
Cost of bike at Danny´competitor= 
Cost of bike at Danny´s competitor= 
∴ Cost of bike at Danny´s competitor is $511.5.
Answer: The median number of posts made is 8.5
To simulate the probability in a spinner divide the spinner into colors depending on the probability each color represents.
<h3>What does the word "probability" mean?</h3>
This word refers to the likelihood for an event to occur. Moreover, it is often expressed either as a fraction, a percentage, or a number.
<h3>How to create a spinner to simulate probability?</h3>
In this case, each of the colors represents a probability:
- Green 20%
- Blue 1/4 or 25%
- Yellow 2/5 oe 40%
- Orange 15%
Due to this, the best is to divide the spinner by colors and considering the percentanges of each color. For example 40% of the spinner should be red, while 15% should be orange.
Learn more about spinner in: brainly.com/question/24280611
#SPJ1
Answer:
(1) False
(2) False
(3). False
(4) False
Step-by-step explanation:
According to the problem, calculation of the given data are as follows,
(1). Given, 149 + 769 = 819
By calculating 149 + 769 = 918
Hence, False
(2). Given, 556 + 336 = 826
By calculating 556 + 336 = 892
Hence, False
(3). Given, 458 - 248 = 238
By calculating 458 - 248 = 210
Hence, False
(4). Given, 658 - 228 = 438
By calculating 658 - 228 = 430
Hence, False
Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.
