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Licemer1 [7]
2 years ago
7

What number is represented by −3x²+√2x+1/2 when x=√2?

Mathematics
1 answer:
Mila [183]2 years ago
6 0

Answer:

at x = \sqrt{2},  -3x^{2} + \sqrt{2}x + \frac{1}{2} = -3.5

Step-by-step explanation:

The given equation is -3x^{2} + \sqrt{2}x + \frac{1}{2}

Now, substitute the value of x = \sqrt{2} in the above equation.

The given equation simplifies to,

-3(\sqrt{2})^{2} + (\sqrt{2})(\sqrt{2}) + \frac{1}{2}

now, \sqrt{2} . \sqrt{2}  = 2, \textrm{and} (\sqrt{2} )^{2} = 2

So, the equation become

-3(2) + 2 + (1/2) = -6 + 2 + \frac{1}{2}   = -4 + \frac{1}{2} = \frac{-8 + 1}{2}  = \frac{-7}{2}  

= -3.5

So, at x = \sqrt{2},  -3x^{2} + \sqrt{2}x + \frac{1}{2} = -3.5

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Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil
Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 83, \sigma = 3

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 83}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0
3 years ago
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