Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Answer:
Approximate of error = 11.11 % (Approx.)
Step-by-step explanation:
Given:
Exact value = 50
Approximate value = 45
Find:
Approximate of error
Computation:
Approximate of error = [(Exact value - Approximate value)/Approximate value]100
Approximate of error = [(50 - 45)/45]100
Approximate of error = [(5)/45]100
Approximate of error = [0.11111]100
Approximate of error = 11.11 % (Approx.)
Answer:
you cant answer it without a calculator
Step-by-step explanation:
press shift - then cos then whatever u need to do to get a
The equation that models this situation is z = 7.9y + 12.
A linear equation is a function that has a single variable raised to the power of 1. An example is x = 4y + 2.
Where:
- 2 is the constant
- x = dependent variable
- y = independent variable
From the equation given, 12 would be the constant, the independent variable would be 7.9 and z would be the dependent variable.
z = 7.9y + 12
Here is the complete question: A barrel of oil was filled at a constant rate of 7.9 gal/min. The barrel had 12 gallons before filling began. write an equation in standard form to model the linear situation.
A similar question was answered here: brainly.com/question/2238405
