6x−4=2(3x−2)
2 answers:
You might be interested in
Total = Principal * [1 + (rate/n)]^n*years
Where "n" is the compounding periods per year
Total = 12,000 * (1+(.05/4))^(4*4)
Total = 12,000 * (1.0125)^(16)
Total = 12,000 * <span> <span> <span> 1.2198895477 </span> </span> </span> <span> </span>
Total = <span> <span> </span></span><span><span><span>14,638.67</span>
</span> </span>
Where "n" is the compounding periods per year
Total = 12,000 * (1+(.05/4))^(4*4)
Total = 12,000 * (1.0125)^(16)
Total = 12,000 * <span> <span> <span> 1.2198895477 </span> </span> </span> <span> </span>
Total = <span> <span> </span></span><span><span><span>14,638.67</span>
</span> </span>