Ask question

Ask question

All categories

3 years ago

10

Enter the missing value into the box to complete the ratio comparing 6 yards to 9 feet.

2 answers:

Damm [24]3 years ago

4 0

2/3 to 1 is the correct answer

zavuch27 [327]3 years ago

3 0

2/3 to 1 is correct. Can i be brainliest! It will help alot!

You might be interested in

PLZ HELP QUESTION IN PICTURE!!

BlackZzzverrR [31]

Answer:

see attached

Step-by-step explanation:

Each spot in the triangle is the sum of the two numbers immediately above. The middle number of row 2 will be 1+1 = 2. The two numbers in row 3 will be 1+2 = 3 and 2+1 = 3. It continues like this. The second number in each row is the row number. Each row is symmetrical about the center.

6 0

3 years ago

Please help! Will mark brainliest

Marina CMI [18]

Answer:

30 degrees but I have to write more stuff so brainly will let me submit my answer

8 0

3 years ago

Read 2 more answers

Fill in the numbers to find a Sum

Alekssandra [29.7K]

Answer:

The numbers are -15 and 100

$\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}$

Step-by-step explanation:

we have

$\frac{2}{10} +\frac{x}{100} =\frac{5}{y}$

Solve the left side

$\frac{2}{10} +\frac{x}{100} =\frac{20+x}{100}$

so

$\frac{20+x}{100}=\frac{5}{y}$

equate the numerators and the denominators

20+x=5 ------> x=5-20=-15

100=y -------> y=5

therefore

The numbers are -15 and 100

$\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}$

4 0

3 years ago

Help i need Help im struggling

HACTEHA [7]

Answer:

c.2,400 I think is c. nose you

Step-by-step explanation:

╮(╯_╰)╭

8 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

So

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

3 years ago