1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentinak56 [21]
3 years ago
8

F(x)=x^3-x^2-10x-8 ; x+1​

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

i think it's f=x2−x−10

Step-by-step explanation:

You might be interested in
Inverse square root (x+3)​
QveST [7]

Answer:

The inverse function is f(x) = x^2 - 3

Step-by-step explanation:

To find the inverse of any function, start by switching the x and f(x) values.

f(x) = √(x + 3)

x = √(f(x) + 3)

Now solve for the new f(x). The result will be your inverse function.

x = √(f(x) + 3)

x^2 = f(x) + 3

x^2 - 3 = f(x)

8 0
3 years ago
Rita started baking at 7:45 AM and finished at 8:12 am. How long did it take her? Give your answer in minutes
Firdavs [7]
 The answer is 27 minutes long
7 0
2 years ago
Read 2 more answers
I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
3 years ago
X/-5+3=-2 <br> What is it step by step
son4ous [18]

Answer:

Step-by-step explanation:

X/-5+3=-2

Collecting like terms

x/-5 = -2 - 3

x/-5 = -5

Multiply each term by -5

-5(x/-5) = -5(-5)

x = 25

7 0
3 years ago
Use proportions to solve each of the problems below. Homework Help ✎
Yakvenalex [24]

Answer:

Question 2:

45 pages 700 pages  

-------------- = -------------  

1 hour X hours  

1 x 700= 700  

700/ 45= 15 and 5/9  

15 and 5/9 hours  

Question 3:

\frac{250}{3} \\ = 88.33 lbs

7 0
3 years ago
Other questions:
  • Show me how solve the problem 30,402÷107
    15·2 answers
  • There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45
    10·1 answer
  • $3 hours worked for 12;9 hours worked for $36
    14·1 answer
  • One number is seven more than three times another number. If the sum of the numbers is 15, find the numbers.
    13·1 answer
  • You drank 8/9 cups of orange juice with your breakfast. If this is 2/3 of the amount that was in the container, how much was in
    6·1 answer
  • Justin wants to rent a boat and spend at most 36. The boat costs 6 per hour, and Justin has a discount coupon for 4 off. What ar
    11·1 answer
  • How many corners are in a rectangle and how many flat faces
    15·2 answers
  • Lydia read 1/5 of her book last week. this week she read 3 times as much as she read last week. write an expression to show how
    14·1 answer
  • What’s the answer 3y+5&lt;10
    15·1 answer
  • How to calculate all possible combinations.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!