I think 4.2 x 10^6 is the answer you're looking for.
Answer:
https://demo.tds.cambiumast.com/DesmosForAssessments/TDSCalculator.html?mode=fl_scirestricted
Step-by-step explanation:
Answer: 201 calls
Step-by-step explanation: 33-19=14
14/0.07=200
201x0.07=33.07
33.07>33
Answer:
h=3t+12
Step-by-step explanation:
C
Answer:
P( At least one of the two cards was a heart)=7/16
Step-by-step explanation:
The solution to this question can be found in two ways.
First way: Since total number of heart in a deck are four,
Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart=
×
=
Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- 
=
Second way:
Probability that first card drawn is a heart and the second one is not a heart=
×
=
Probability that the first card drawn is not a heart and the second one is a heart=
×
=
Probability that both cards drawn are hearts=
×
=
Adding all these probabilities, we have the probability that at least one of the card drawn was heart= 