Answer:
int ComputeFibonacci(int N) {
if(N == 0)
return 0;
else if (N == 1)
return 1;
else
return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);
}
Explanation:
Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.
For example,
If N = 4 as in the main part:
ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3
ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2
ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0 = 1
*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.
Make a Fist, hold, and stretch your fingers is the correct answer
Answer:
When a sentinel is used in a (pretest/post test) loop to validate data, the loop repeats as long as the input is (valid/invalid).
Explanation:
Required
Fill in the gaps
Sentinel are used to validate or invalidate loops (pretest and post test loops).
Since , some parts of the brackets have aready been filled, we simply complete the blanks with the opposite of the term in the bracket. i.e. the opposite of post test is pretest and the opposite of valid is invalid.
<em>So, the blanks will be filled with pretest and invalid.</em>
<span>The answer is : Increasing the key length of DES would protect it against brute force attacks. </span>Brute force is when the attacker tries every key knowing that one will eventually work. <span>Key length increase proportionally increases the key space, having a keyspace l</span>arge enough that it takes too much time and money to accomplish a brute force attack.
