First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
Hello there! So, this is a quadrilateral and quadrilaterals equal 360 degrees. Let’s combine like terms to start off. 39x + 9 = 360. First, let’s subtract 9 from both sides to get 39x = 351. Next, divide each side y 39 to isolate the “x”. When you do that, x = 9. Now, let’s plug in the values for each, when you do, here are the final answers.
x = 9
E = 75 degrees
F = 91 degrees
G = 89 degrees
H = 105 degrees
Those are all of the angle measurements, but it wants the measurement of angle H. Therefore, that angle measurement is 105 degrees.
The first one is "four tenths".
The second one is "four thousandths".
I hope this helps you
x.x-2.3x+9-21=0
(x-3)^2-21=0
(x-3)^2=21
Answer:
f^-1 (x) = x/5
Step-by-step explanation:
f(x) = 5x
Replace f(x) with y
y= 5x
Exchange x and y
x = 5y
Solve for y
Divide each side by 5
x/5 = 5y/5
x/5 = y
The inverse is x/5
