We assume the two numbers are x and (x+1)
so x^2+(x+1)^2=421
x^2+(x^2+2x+1)=421
2x^2+2x-420=0
According to the formula of quadratic
x=14 or-15
cuz we know the two numbers are integers
so x=14
therefore the other number is 15
To make sure that's correct
14^2+15^2=421
Hope that helps you!!
Answer:
No.
Step-by-step explanation:
All numbers that are able to be represented as fractions with whole numbers are rational.
Answer:
<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>
Step-by-step explanation:



They are the same , hope this helps :)
Answer:
15
Step-by-step explanation:
Difference in distances = 75-60 = 15 miles
So Car A travels 15 miles more than Car A in an hour
Answered by Gauthmath