Answer:
x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Step-by-step explanation:
1−2sin2 x≤−sin x ⇒ (2sin x+1)(sin x−1)≥0
sin x≤−1/2 or sin x≥1
−5π/6+2nπ≤x≤−π/6+2nπ or , n ϵ I x=(4n+1)π/2, n ϵ I⇒ -5π6+2nπ≤x≤-π6+2nπ or , n ϵ I x=4n+1π2, n ϵ I (as sin x = 1 is valid only)
In general⇒ In general x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
5) m<1 = 60
6) m<2 = 30
7) m<3 = m<1 = 60
8) m<4 = m<2 = 30
90/18 = 5
9) m<1 = m<3 = 85
10) m<2 = m<4 = 5
Okay so lets look at this.
So we have 5/5 girls.
2/5 of them are playing softball. An equal number of girls signed up to play pitcher, infield, and outfield. This means that each one is 1/3.
So out of 2/5 of the girls, there is 1/3 of the 2/5 that signed up to play outfield.
The answer can be solved with multiplication of fractions.
2/5 * 1/3 is 2/15. So 2/15 of the girls in the school signed up to play outfield.
Answer: 2/15 or 0.133
Answer:
1011×1011 = 11110011
Step-by-step explanation:
11 in binary is 1011
121 in binary is 1111001
