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GuDViN [60]
4 years ago
7

A.What quadrant would it land on? B. What point would it be? X(____,____)

Mathematics
1 answer:
yanalaym [24]4 years ago
7 0
Point X would land in quadrant 4 because if the first # in the point is positive and the second is negative then it will always land in quadrant 4.  
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What’s the surface area
Elodia [21]
The answer would be 202 inches
7 0
3 years ago
For X a binomial random variable with n=5 and p=1/4, answer the following
mash [69]
Recall that for X\sim\mathrm{Bin}(n,p), i.e. a random variable X following a binomial distribution over n trials and with probability parameter p,

\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}

So you have

\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26

\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)
=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}
=\dfrac{375}{1024}\approx0.37

The expected value of X\sim\mathrm{Bin}(n,p) is simply np, while the standard deviation is \sqrt{np(1-p)}. In this case, they are \dfrac54=1.25 and \sqrt{\dfrac{15}{16}}\approx0.97, respectively.
7 0
3 years ago
10 tan = ___pounds?
tensa zangetsu [6.8K]
(I'm guessing you mean ton)
10 ton = 20,000 pounds
8 0
3 years ago
Read 2 more answers
Part I
tino4ka555 [31]

Answer:

Step-by-step explanation:

I know that the two means are are 11.28 and 12.

I could be wrong but I did the math 5 times.

3 0
3 years ago
Read 2 more answers
Un terreno de 4200 metros cuadrados de superficie se quiere dividir en dos lotes de manera que el lote menor sea tres cuartas pa
lions [1.4K]

Answer:

El lote menor tendrá 1800 m^2

El lote mayor tendrá 2400 m^2

Step-by-step explanation:

Definamos las variables:

M = superficie del lote mayor

m = superficie del lote menor.

Sabemos que el terreno tiene en total 4200 m^2

Entonces:

M + m = 4200 m^2.

Y queremos que el lote menor sea 3/4 del lote mayor, entonces:

m = (3/4)*M

Podemos reemplazar esto en la ecuación de arriba para obtener:

M + ( (3/4)*M) = 4200 m^2.

Y ahora podemos resolver esto para M

M + (3/4)*M = 4200m^2

M*(1 + 3/4) = 4200m^2

M*(4/4 + 3/4) = 4200 m^2

M*(7/4) = 4200m^2

M = (4/7)*(4200m^2) = 2400m^2

Esto significa que la superficie del mayor lote es 2400 m^2

Y la superficie del menor se puede obtener con la ecuación:

m = (3/4)*M

m = (3/4)*2400m^2 = 1800m^2

La superficie del lote menor es 1800m^2

4 0
3 years ago
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