Answer:
55,30
Step-by-step explanation:
just did it
Answer:
o
Step-by-step explanation:
if x = 0 ,y =10
4×0+10
=10
if x = 1, y = 6
=4×1 + 6
=4 +6
=10
if x = 2, y = 2
=4×2 +2
=8 + 2
=10
u can substitute any value for x and y ...i have only used positive values here
(1+x^2)^8
=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)
=1+8x^2+28x^4+56x^6+70x^8+....)
For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.
1.01=(1+0.1^2) => x=0.1 in the above expansion
(1.01)^8
=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]
=1+0.08+0.0028+0.000056 (+0.00000070)
=1.082856 (approximately)
Answer:
2 (B)
Step-by-step explanation:
Showing the relationships among concepts.
