Answer:
943,281
Step-by-step explanation:
Just move the 3 up a value
If it's in the ten's place, then move it to the hundred's place value.
If it's in the hundred's place, then move it to thousand's place value.
So on and so on...
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards.
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards.
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x.
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
=> Area, A
= 2x (y1 - y2)
= 2x (18 - x^2 - 2x^2 + 9)
= 2x (27 - 3x^2)
= 54x - 6x^3
For area to be maximum, dA/dx = 0 and d²A/dx² < 0
=> 54 - 18x^2 = 0
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants)
d²A/dx² = - 36x < 0 for x = √3
=> maximum area
= 54(√3) - 6(√3)^3
= 54√3 - 18√3
= 36√3.
Answer:
900 yd²
Step-by-step explanation:
You can draw the pattern that would need to be folded to make the figure, then find the area of that pattern (or "net"). It consists of a rectangle 10 yards wide and 60 yards long, together with another that is 20 yards long and 15 yards wide. The total area is the sum of these ...
... area = (60 yd)(10 yd) + (20 yd)(15 yd)
... = 600 yd² +300 yd²
... = 900 yd²
Answer:
3x + 21
Step-by-step explanation:
3(x + 7) Distribute
3x + 21
