Option 4 with the y-intercept at (0,-3)
This is a geometric sequence:
First month: 8
Second month: 8 * 1.02
Third month: 8*1.02^2
Fourth month 8* 1.02^3
...
nth month: 8 * 1.02 ^(n-1)
Sum of the first 9 terms (months) = a[1 -r^n] / (1 - r) = 8* [1 - 1.02^9] / (1 - 1.02) = 78.04
Answer: approximately 78 bikes.
Yes. 1 of them is ' a quad. is a trap.' and the 2nd one is 'trap. has at least 1 pair of parallel sides'
Answer:
Dont know the answer but good luck
Step-by-step explanation:
Answers:
4; 20; 3x² - 4x + 3; 52; 17
Step-by-step explanation:
f(-1): replace x in f(x) = x² + 3 with -1: f(-1) = (-1)² + 3 = 4
f(-4) + g(-1) = (-4)² + 3 + <em>2(-1) + 3</em> = 16 + 3 <em>- 2 + 3</em> = 20 <em>(since g(x) = 2X + 3)</em>
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3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6 = 3x² - 4x + 3
f(g(2)): First, evaluate g(2). It is g(2) = 2(2) + 3 = 7. Next, use this output, 7, as the input to f(x): f(g(x)) = (7)² + 3 = 49 + 3 = 52
g(f(2)): First, evaluate f(x) at x = 2: f(2) = (2)² + 3 = 7. Next, use this 7 as the input to g(x): g(f(2)) = g(7) = 2(7) + 3 = 17