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3 years ago

Write a number in which value of the digit 3 is 10 times as much as the value of the digit 3 in 942381 show your thinking.

Mathematics

2 answers:

choli [55]3 years ago

8 0

Answer:

943,281

Step-by-step explanation:

Just move the 3 up a value

If it's in the ten's place, then move it to the hundred's place value.

If it's in the hundred's place, then move it to thousand's place value.

So on and so on...

7nadin3 [17]3 years ago

3 0

Answer:

943281

Step-by-step explanation:

The three in this number 942381 is in the hundreds place. If you multiply 300 by 10, you get 3,000. The thousands are in the third digit area. So, it is the answer.

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Could you please name the place value to which each number was rounded.3.695 to 4

Svetradugi [14.3K]

Answer:

The place value to which the number is rounded is unit place.

Step-by-step explanation:

Here, the number 3.695 is rounded to the number 4 and we have to name the place value to which the number is rounded.

Here, the place value to which the number is rounded is unit place.

And the name of the rounding is the rounding to the nearest whole number i.e. there will be no fractional part in the rounded number.

Another example is the number 0.917 is rounded to the nearest whole number to give 1. (Answer)

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3 years ago

The area of a square is 64 n 36square units. What is the side length of one side of the square? 8 nt 6 units 8 n Superscript 18

tamaranim1 [39]

Answer:

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Step-by-step explanation:

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3 years ago

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How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

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3 years ago

If r=7 and S=10, find R. Round answer to the nearest tenth.

ivolga24 [154]

I believe the answer is 35 degrees, or A.

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3 years ago

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Write an absolute value inequality for the graph below.<br>use x for your variable.<br>

Alenkasestr [34]

Step-by-step explanation:

The magnitude of x is equal or less than 7.