The position of the centre of gravity of an object affects its stability. The lower the centre of gravity (G) is, the more stable the object. The higher it is the more likely the object is to topple over if it is pushed. Racing cars have really low centres of gravity so that they can corner rapidly without turning over.
Increasing the area of the base will also increase the stability of an object, the bigger the area the more stable the object. Rugby players will stand with their feet well apart if they are standing and expect to be tackled.
Answer: E = 5.80*10^-13 J
Explanation:
Given
We use the law of conservation of momentum to solve this
Momentum before breakup = momentum after breakup
0 = m1v1 + m2v2
0 = 238m * -2.2*10^5 + 4m * v2
0 = -523.6m m/s + 4m * v2
v2 * 4m = 523.6m m/s
v2 = 523.6 m m/s / 4m
v2 = 130.9*10^5 m/s
v2 = 1.31*10^7 m/s
Using this speed in the energy equation, we have
E = 1/2m1v1² + 1/2m2v2²
E = 1/2 * (238 * 1.66*10^-27) * -2.2*10^5² + 1/2 * (4 * 1.66*10^-27) * 1.31*10^7²
E = [1/2 * 3.95*10^-25 * 4.84*10^10] + [1/2 * 6.64*10^-27 * 1.716*10^14]
E = (1/2 * 1.911*10^-14) + (1/2 * 1.139*10^-12)
E = 9.56*10^-15 + 5.7*10^-13
E = 5.80*10^-13 J
Answer:
v₂ = 0.56 m / s
Explanation:
This exercise can be done using Bernoulli's equation
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
Where points 1 and 2 are on the surface of the glass and the top of the straw
The pressure at the two points is the same because they are open to the atmosphere, if we assume that the surface of the vessel is much sea that the area of the straw the velocity of the surface of the vessel is almost zero v₁ = 0
The difference in height between the level of the glass and the straw is constant and equal to 1.6 cm = 1.6 10⁻² m
We substitute in the equation
+ ρ g y₁ = + ½ ρ v₂² + ρ g y₂
½ v₂² = g (y₂-y₁)
v₂ = √ 2 g (y₂-y₁)
Let's calculate
v₂ = √ (2 9.8 1.6 10⁻²)
v₂ = 0.56 m / s
Is this a multiple choice question?
If not, well then the answer is that the volcano sort of sinks into the ground. Like it sort of subducts.
Hope this helped!!!:)
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C. because if you push a ball on one side and on the other side with the same amount of force at the same time it won’t move.
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