Answer:
- quality factor (Q) = 69.99
- inductor = 1.591 x 10⁻⁴ H
- capacitor = 3.248 x 10⁻¹⁰ F
Explanation:
Given;
resonance frequency (F₀) = 700 kHz
resistor, R = 10 Ohm
bandwidth (BW) = 10 kHz
bandwidth (BW) 

make L (inductor) the subject of the formula


make C (capacitor) the subject of the formula

quality factor (Q) 
quality factor (Q) = 69.99
To develop this problem it is necessary to apply the concepts related to a magnetic field in spheres.
By definition we know that the magnetic field in a sphere can be described as

Where,
a = Radius
z = Distance to the magnetic field
I = Current
Permeability constant in free space
Our values are given as
diameter of the sphere then,

Thus z = a



Re-arrange to find I,



Therefore the current at the pole of this sphere is 
300 divide 1.5=200 let me know if this was helpful
The Doppler effect occurs when a source of sound or light
moves either toward or away from the observer.
Answer:
By turning the vehicle "ON" position you can check to see if the gauges light works.
When we switch ON or turn a key to ON the engine, we can find all the gauges working or not.