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krek1111 [17]
3 years ago
7

On a bet, you try to remove water from a glass by blowing across the top of a vertical straw immersed in the water. What is the

minimum speed you must give the air at the top of the straw to draw water upward through a height of 1.6cm?
Physics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

       v₂ = 0.56 m / s

Explanation:

This exercise can be done using Bernoulli's equation

        P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Where points 1 and 2 are on the surface of the glass and the top of the straw

The pressure at the two points is the same because they are open to the atmosphere, if we assume that the surface of the vessel is much sea that the area of ​​the straw the velocity of the surface of the vessel is almost zero v₁ = 0

The difference in height between the level of the glass and the straw is constant and equal to 1.6 cm = 1.6 10⁻² m

We substitute in the equation

         P_{atm} + ρ g y₁ = P_{atm} + ½ ρ v₂² + ρ g y₂

         ½ v₂² = g (y₂-y₁)

        v₂ = √ 2 g (y₂-y₁)

Let's calculate

        v₂ = √ (2 9.8 1.6 10⁻²)

       v₂ = 0.56 m / s

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6 Newtons to the left.

Explanation:

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One of the many by products of uranium is radioactive plutonium, which has a half life of approximatley 25000 ytears. if some of
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Answer:

0.9972 fraction of plutonium will remain after 100 years.

Explanation:

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Let the initial mass of plutonium be = A_o

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