Explanation:
It is given that,
Mass of an electron, ![m=9.11\times 10^{-31}\ kg](https://tex.z-dn.net/?f=m%3D9.11%5Ctimes%2010%5E%7B-31%7D%5C%20kg)
Initial speed of the electron, ![u=3\times 10^5\ m/s](https://tex.z-dn.net/?f=u%3D3%5Ctimes%2010%5E5%5C%20m%2Fs)
Final speed of the electron, ![v=7\times 10^5\ m/s](https://tex.z-dn.net/?f=v%3D7%5Ctimes%2010%5E5%5C%20m%2Fs)
Distance, d = 5 cm = 0.05 m
(a) The acceleration of the electron is calculated using the third equation of motion as :
![a=\dfrac{v^2-u^2}{2d}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2d%7D)
![a=\dfrac{(7\times 10^5)^2-(3\times 10^5)^2}{2\times 0.05}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%287%5Ctimes%2010%5E5%29%5E2-%283%5Ctimes%2010%5E5%29%5E2%7D%7B2%5Ctimes%200.05%7D)
![a=4\times 10^{12}\ m/s^2](https://tex.z-dn.net/?f=a%3D4%5Ctimes%2010%5E%7B12%7D%5C%20m%2Fs%5E2)
Force exerted on the electron is given by :
![F=m\times a](https://tex.z-dn.net/?f=F%3Dm%5Ctimes%20a)
![F=9.11\times 10^{-31}\times 4\times 10^{12}](https://tex.z-dn.net/?f=F%3D9.11%5Ctimes%2010%5E%7B-31%7D%5Ctimes%204%5Ctimes%2010%5E%7B12%7D)
![F=3.64\times 10^{-18}\ N](https://tex.z-dn.net/?f=F%3D3.64%5Ctimes%2010%5E%7B-18%7D%5C%20N)
(b) Let W is the weight of the electron. It can be calculated as :
![W=mg](https://tex.z-dn.net/?f=W%3Dmg)
![W=9.11\times 10^{-31}\times 9.8](https://tex.z-dn.net/?f=W%3D9.11%5Ctimes%2010%5E%7B-31%7D%5Ctimes%209.8)
![W=8.92\times 10^{-30}\ N](https://tex.z-dn.net/?f=W%3D8.92%5Ctimes%2010%5E%7B-30%7D%5C%20N)
Comparison,
![\dfrac{F}{W}=\dfrac{3.64\times 10^{-18}}{8.92\times 10^{-30}}](https://tex.z-dn.net/?f=%5Cdfrac%7BF%7D%7BW%7D%3D%5Cdfrac%7B3.64%5Ctimes%2010%5E%7B-18%7D%7D%7B8.92%5Ctimes%2010%5E%7B-30%7D%7D)
![\dfrac{F}{W}=4.08\times 10^{11}](https://tex.z-dn.net/?f=%5Cdfrac%7BF%7D%7BW%7D%3D4.08%5Ctimes%2010%5E%7B11%7D)
Hence, this is the required solution.
Answer:
Explanation:
a) ωp = 2π radians / 1.7 s = <u>3.7 rad/s</u>
b) ωs = 3.7 rad/s(9.5 cm / 4.5 cm) = 7.8 rad/s
v = (ωs)R = 7.8(65) = 507 cm/s or <u>5.1 m/s</u>
c) ωs = 3.5 m/s / 0.65 m = 5.38 rad/s
ωp = 5.38(4.5 cm / 9.5 cm) = 2.55 rad/s
t = θ/ω = 2π / 2.55 = 2.463... <u>2.5 s</u>
Nope.
Energy is directly proportional to frequency. and when you calculate energy, you multiply frequency with a constant number called "Planck's Constant"
E = hf
Hope this helps!
Answer:
500km
Explanation:
Given parameters:
Speed = 200km/hr
Time taken = 2.5hrs
Unknown:
Distance = ?
Solution:
To solve this problem, we use the speed, time and distance equation.
Therefore;
Distance = Speed x time
So;
Distance = 200 x 2.5 = 500km
Answer:
Hz
Explanation:
In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;
V(t) = V sin (ωt + Ф) -----------------(i)
Where;
V = amplitude value of the voltage
ω = angular frequency = 2 π f [f = cyclic frequency or simply, frequency]
Ф = phase difference between voltage and current.
<u><em>Now,</em></u>
From the question,
V(t) = 230 sin (100t) ---------------(ii)
<em><u>By comparing equations (i) and (ii) the following holds;</u></em>
V = 230
ω = 100
Ф = 0
<em><u>But;</u></em>
ω = 2 π f = 100
2 π f = 100 [divide both sides by 2]
π f = 50
f =
Hz
Therefore, the frequency of the voltage is
Hz