Answer
given,
weight of the oak board = 600 N
Weight of Joe = 844 N
length of board = 4 m
Joe is standing at 1 m from left side
vertical wire is supporting at the end.
Assuming the system is in equilibrium
T₁ and T₂ be the tension at the ends of the wire
equating all the vertical force
T₁ + T₂ = 600 + 844
T₁ + T₂ = 1444...........(1)
taking moment about T₂
T₁ x 4 - 844 x 3 - 600 x 2 = 0
T₁ x 4 = 3732
T₁ = 933 N
from equation (1)
T₂ = 1444 - 933
T₂ = 511 N
Answer:
V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s
Explanation:
The volume flow rate of the blood in the artery can be given by the following formula:
where,
V = Volume flow rate = ?
A = cross-sectional area of artery = πd²/4 = π(0.004 m)²/4 = 1.26 x 10⁻⁵ m²
v = velcoity = 0.28 m/s
Therefore,
<u>V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s</u>
Given that,
Atmospheric Pressure = 14.7 psi
Cooking Pressure = 14.7 +11.1 = 25.8 psi
Take, Atmospheric Temperature = 25 °C
Cooking Temperature = ??
Since, we know that Gas equation is given by:
PV = nRT
or
P ∝ T
P1 / T1 = P2 / T2
14.7/ 25 = 25.8/ T2
T2 = 25*25.8/14.7
T2 = 43.87 °C
The cooking pressure will be 43.87 °C.
