(1 - 2x)⁴
(1 - 2x)(1 - 2x)(1 - 2x)(1 - 2x)
[1(1 - 2x) - 2x(1 - 2x)][1(1 - 2x) - 2x(1 - 2x)]
[1(1) - 1(2x) - 2x(1) - 2x(-2x)][1(1) - 1(2x) - 2x(1) - 2x(-2x)]
(1 - 2x - 2x + 4x²)(1 - 2x - 2x + 4x²)
(1 - 4x + 4x²)(1 - 4x + 4x²)
1(1 - 4x + 4x²) - 4x(1 - 4x + 4x²) + 4x²(1 - 4x + 4x²)
1(1) - 1(4x) + 1(4x²) - 4x(1) - 4x(-4x) - 4x(4x²) + 4x²(1) - 4x²(4x) + 4x²(4x²)
1 - 4x + 4x² - 4x + 16x² - 16x³ + 4x² - 16x³ + 16x⁴
1 - 4x - 4x + 4x² + 16x² + 4x² - 16x³ - 16x³ + 16x⁴
1 - 8x + 24x² - 32x³ + 16x⁴
The correct answer for the question that is being presented above is this one: "28 in^2."
We have to get the individual area of each surface.
A1 = 1*3*2 = 6
A2 = 1*3*2 = 6
A3 = 1*2*2 = 4
A4 = 2*3*2 = 12
Area = A1 + A2 + A3 + A4
Area = 6 + 6 + 4 + 12
Area = 28 in^2
Input Data :
Point 1 ( x A , y A ) = (-6, -2)
Point 2 ( x B , y B ) = (1, -6)
Objective :
Find the distance between two given points on a line.
Formula :
Distance between two points = √ ( x B − x A )2 + ( y B − y A ) 2
Solution :
Distance between two points = √ ( 1 - -6 ) 2 + ( − 6 − − 2 ) 2
= √ 7 2 + ( − 4 ) 2
= √ 49 + 16
= √ 65 = 8.0623
Distance between points (-6, -2) and (1, -6) is 8.0623
Or 8.
Best of luck!!
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Answer:
Range is [1, ∞)
Step-by-step explanation:
The values of x can be 1 up to infinity (the domain).
When x = 1 , f(x) = 1^2 = 1
when x = ∞, x^2 = ∞
So the range is [1, ∞)
