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Alexxx [7]
2 years ago
13

Simplify the following expression and show your work in details please .

Mathematics
1 answer:
Igoryamba2 years ago
7 0

Answer:

= -2

Step-by-step explanation:

6t + 3 (1 - 2t) - 5

= 6t + 3 - 6t - 5

6t and -6t cross out as they equal 0, so we are left with only +3 and -5

+3 - 5 = -2

= -2 ---> final solution

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Please help and explain it would be very helpful​
iris [78.8K]
So for the first one think of it as decimals so it’s easier: 9.20-7.35, subtract and it would be 1.85 so since we use decimals to make it easier it isn’t actually a decimal so it would be 2 hours and 25 minutes. And for the second one you just add 50 minutes to that and you would get 3 hours and 15 minutes.

6 0
3 years ago
A jar contains black and white marbles in the ratio 2:5. If the jar contains total of 35 marbles, how many of the marbles are bl
Svet_ta [14]

Answer:

10 black marbles

Step-by-step explanation:

Let black marbles be=2x

Then white marbles=5x

Total marbles=7x which in turn is equal to 35. Hence x=5

Black marbles=2*5=10

H2H

8 0
2 years ago
Two ships leave the same port at the same time. Two hours later ship A has traveled 12 miles and ship B has traveled 8 miles.
MakcuM [25]

Answer:

the angle between their paths is <em>100.8°</em>

Step-by-step explanation:

From the given information, you can construct a triangle, just like the one in the figure.

We will use the <em>Cosine Rule</em> which is:

c² = b² + a² - 2 b c cos(θ)

where

  • c = 16 miles
  • b = 8 miles
  • a = 12 miles

Therefore,

2 b c cos(θ) = b² + a² - c²

cos(θ) = (b² + a² - c²) / 2 b c

θ = cos⁻¹( (b² + a² - c²) / (2 b c) )

θ = cos⁻¹( (8² + 12² - 16²) / 2(8)(16) )

<em>θ = 100.8°</em>

<em></em>

Therefore, the angle between their paths is <em>100.8°</em>

4 0
3 years ago
A small combination lock on a suitcase has 55 ​wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar
den301095 [7]
Suppose a_n is the number of possible combinations for a suitcase with a lock consisting of n wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for n+1 wheels, or a_{n+1} is given recursively by the formula

a_{n+1}=9a_n

starting with a_1=10 (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n

This means a lock with 55 wheels will have

a_{55}=10\times9^{54}

possible combinations (a number with 53 digits).
7 0
3 years ago
People who are good with geometry please help:
alexandr402 [8]
C …………………………..…..SSS
8 0
2 years ago
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