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3 years ago

A worm squiggles 10 cm in 5 minutes. What was it average speed

Mathematics

1 answer:

ololo11 [35]3 years ago

5 0

2 centimeters per minute

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Mark wrote the highest score he made on his new video game as the product of 70x6,000. Use the associative and commutative prope

Lelu [443]

You need a caculater that is what you need tho

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3 years ago

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(За + 2b – 7) - (4) — 10)

Sedaia [141]

Answer:=3a+2b−21

Step-by-step explanation:

Let's simplify step-by-step.

3a+2b−7−4−10

=3a+2b+−7+−4+−10

Combine Like Terms:

=3a+2b+−7+−4+−10

=(3a)+(2b)+(−7+−4+−10)

=3a+2b+−21

4 0

3 years ago

Which is the equation of a hyperbola centered at the origin with y-intercepts +12 -12, and asymptote y=3x/2

dangina [55]

Answer:

$\frac{y^2}{144}-\frac{x^2}{64}=1$

Step-by-step explanation:

The equation of a hyperbola centered at the origin with vertices on the y-axis is given by: $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

The vertices of the hyperbola are the y-intercepts (0,12) and (0,-12)

This implies that:

$2a=|12--12|$

$2a=24$

$a=12$

The asymptote equation of a hyperbola is given by:

$y=\pm\frac{a}{b}x$

The given hyperbola has asymptote: $y=\pm\frac{3}{2} x$

By comparison; $\frac{a}{b}=\frac{3}{2}$

$\implies \frac{12}{b}=\frac{12}{8}$

$\implies b=8$

The required equation is:

$\frac{y^2}{12^2}-\frac{x^2}{8^2}=1$

$\frac{y^2}{144}-\frac{x^2}{64}=1$

6 0

3 years ago

Read 2 more answers

25/8 in a reduced form is what ?

dangina [55]

I think that is the lowest it can go

8 0

3 years ago

A researcher is using a two-tailed hypothesis test with α = .05 to evaluate the effect of a treatment. If the boundaries for the

Solnce55 [7]

Answer:

A. n = 22

Step-by-step explanation:

Hello!

The researcher conducted a one-sample t-tas with the following hypotheses:

H₀: μ = μ₀

H₁: μ ≠ μ₀

α:0.05

The one-sample t-test has "n-1" degrees of freedom and since the hypotheses are two-tailed you know that the rejection region will be divided into two tails with "α/2" for each tail. ± $t_{n-1;1-\alpha /2}$

If α:0.05 then α/2:0.025 and 1-α/2= 0.975

Using the given sample sizes as a reference you look in the table for the corresponding DF for an accumulated probability of 0.975

For n = 22 $t_{21;0.975}= 2.080$

For n= 21 $t_{20;0.975}= 2.086$

For n= 20 $t_{19;0.975}= 2.093$

The correct answer is a) n= 22

I hope this helps!

5 0

3 years ago