Answer:
(a) 45 micro coulomb
(b) 6 micro Coulomb
Explanation:
C = 3 micro Farad = 3 x 10^-6 Farad
V = 15 V
(a) q = C x V
where, q be the charge.
q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb
(b)
V = 2 V, C = 3 micro Farad = 3 x 10^-6 Farad
q = C x V
where, q be the charge.
q = 3 x 10^-6 x 2 = 6 x 10^-6 C = 6 micro coulomb
Answer
18,000
Why?
KE=(1/2)(2000)(18)
Ke=18,000
Answer:
f1= -350cm or -3.5m
f2= 22.1cm or 0.221m
Explanation:
A person is nearsighted when the person's far point is less than infinity. A diverging lens is normally used to correct this eye defect. A diverging lens has a negative focal length as seen in the solution attached.
Farsightedness is when a person's near point is farther than 25cm. This eye defect is corrected using a converging lens. The focal length of a converging lens is positive. This is evident in the solution attached. The near point is also referred to as the least distance of distinct vision.
The slime mold will create a stalk with new spores in it, called a "fruiting body". These spores will make new patches of slime mold. This is a form of asexual reproduction.
<h2>Mark as brainliest?</h2>
Answer:
4000 Hz
Explanation:
An anti-alias filter is usually added in front of the ADC to limit a certain range of input frequencies in order to avoid aliasing. This filter is usually a low pass filter that passes low frequencies but attenuates the high frequencies.
The Nyquist sampling criteria states that the sampling rate should be at least twice the maximum frequency component of the desired signal.
Sampling rate = 2(max input frequency)
From the relation we can find out the cut-off frequency for the anti-aliasing filter.
max input frequency = sampling rate/2
max input frequency = 8100/2 = 4050 Hz
Therefore, 4000 Hz would be an appropriate cut-off frequency for the anti-aliasing filter.
