Answer:
89
Step-by-step explanation:
I took the same exact test 9
Answer:
Sedimentary rocks usually form in visible layers
Step-by-step explanation:
A is wrong because not all igneous rock is formed by pressure
B is wrong because sedimentary rock is usually a surface rock
C is wrong because the rock cycle is sporadic and doesn't always end in igneous rock
D is correct because sedimentary rock is formed from years and years of sediment layering on top of each other
Answer:
RS/VU=ST/UT and ∠S≅∠U
Step-by-step explanation:
we know that
The <u>Side-Angle-Side Similarity Theorem </u>states that: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar
In this problem the included angle is
∠S≅∠U
therefore
side RS must be proportional to side VU and side ST must be proportional to side UT
so
RS/VU=ST/UT
<em>Verify</em>
substitute the given values
12/6=16/8
2=2 -----> is true
therefore
The two sides are proportional
Answer:
Senate
Step-by-step explanation:
Senate
Answer:
V'(t) = 
If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.
Step-by-step explanation:
Given:
V =
, where 0≤t≤40.
Here we have to find the derivative with respect to "t"
We have to use the chain rule to find the derivative.
V'(t) = 
V'(t) = 
When we simplify the above, we get
V'(t) = 
If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.