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3 years ago

The symmetry of a hyperbola with a center at (h, k) only occurs at y = k. True False

2 answers:

7 0

The answer is false because a hyperbola can have many different orientations and still technically be a hyperbola.
~ Please mark my answer as most brainliest if it helped you :) ~

Lyrx [107]3 years ago

4 0

False
Its other axis of symmetry is at x = h.

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Which equals the product of (x – 3)(2x + 1)?

hram777 [196]

Answer:

2x^2 – 5x – 3

Step-by-step explanation:

<u>Apply FOIL method: </u>

=x*2x+x*1+(-3)*2x+(-3)*1

<u>Apply minus-plus rules:</u>

=2xx+1*x-3*2x-3*1

Simplify:

=2x^2 – 5x – 3

Your Answer Is 2x^2 – 5x – 3

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3 years ago

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2 years ago

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Pie

Answer:

Step-by-step explanation:

a= y-k/ (x-h)^2

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1 year ago

I’ve been struggling on this for a while. Someone help!

liberstina [14]

Answer:

D i believe

Step-by-step explanation:

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3 years ago

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PLEASE HELP!

sesenic [268]

Answer:

$36\sqrt{3}$

Step-by-step explanation:

Hi!

Since an equilateral triangle means that every side is equal, our triangle will have 12 on all sides.

To find the height of an equilateral triangle we use $\frac{a\sqrt{3}}{2}$ .

$\frac{12\sqrt{3} }{2} = 6\sqrt{3}$ .

So the height is $6\sqrt{3}$ .

Now we have to solve 12 * $6\sqrt{3}$ ÷ 2.

$12 \cdot 6\sqrt{3} = 72\sqrt{3}$

$72\sqrt{3}\: \div\: 2 = 36\sqrt{3}$ .

Thus, the area of the triangle is $\boxed{36\sqrt{3}}$ .

Hope this helps!

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3 years ago