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pentagon [3]
3 years ago
14

The symmetry of a hyperbola with a center at (h, k) only occurs at y = k. True False

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
7 0
The answer is false because a hyperbola can have many different orientations and still technically be a hyperbola.
~ Please mark my answer as most brainliest if it helped you :) ~
Lyrx [107]3 years ago
4 0
False
Its other axis of symmetry is at x = h.
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-4 1/5+3 2/3+ -1 2/5
Paul [167]

Answer:

-1.9

Step-by-step explanation:

I rounded it to the tenth

8 0
3 years ago
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Which one is correct ?
mina [271]

Answer:

Answer choice B

Step-by-step explanation:

The measures of angles on touching the opposite sides of the circles are always half the lengths of their respective arc. 126/2=63, or answer choice B. Hope this helps!

3 0
3 years ago
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a recipe for soup calls for 4 3/4 cup of water 1/2 teaspoon of salt, and 2 1/2 cups of mixed vegetables. if the recipe yields tw
tekilochka [14]
All we have to do is multiply by two

4 3/4 * 2 = 9 1/2 
1/2 * 2 = 1
2 1/2 * 2 = 5
7 0
3 years ago
100 pts help me please.
Natalija [7]

<u>Answer:</u>

  • Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.

<u>Step-by-step explanation:</u>

We know that:

  • 48 + 8(b) = Carly's expenditure
  • 10(b) = Carly's expenditure
  • 48 + 8b = 10b
  • B = Boxes of cards

<u>Work:</u>

  • 48 + 8b = 10b
  • => 48 + 8b - 8b = 10b - 8b
  • => 48 = 2b
  • => b = 24

<u>Now, let's substitute the value of b into any equation.</u>

  • 10(24)
  • => 240

<u>Hence, Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.</u>

Hoped this helped.

BrainiacUser1357

7 0
2 years ago
What is one possible solution for the triangle below?
elixir [45]
Answer:

segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°

Explanation:

1) Given two side lenghts and one angle you can use sine law:

\frac{sinA}{a} = \frac{sinB}{b} = \frac{sinC}{c}

2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:

\frac{sinZ}{43} = \frac{sin68}{40}

From which you can clear sinZ and get:

sinZ = 43 × sin(68) / 40 = 0.9967

⇒ Z = arcsine(0.9967) ≈ 85.36°


3) The third angle can be determined using 85.36° + 68° + X = 180°

⇒ X = 180° - 85.36° - 68° = 26.64°.

4) Finally, you can apply the law of sine to obtain the last missing length:

\frac{x}{sin(26.64)} = \frac{40}{sin(68)}

From which: x = 40 × sin(26.64°) /  sin(68°) = 19.34 in

The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
5 0
3 years ago
Read 2 more answers
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