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VladimirAG [237]
3 years ago
14

Find the diameter of a cone that has a volume of 56.52 cubic inches and a height of 6 inches. Use 3.14 for pi. a. 3 inches. b. 6

inches. c. 9 inches. d. 12 inches
Mathematics
1 answer:
sergejj [24]3 years ago
3 0
Volume of cone = (1/3)pi*r²h

56.52 = (1/3)*3.14*r²*6

56.52/(2*3.14) = r²

9 = r²

r² = 9

r = √9

r = 3

Diameter = 2*r = 2*3 = 6 inches.    b.
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nadezda [96]

9514 1404 393

Answer:

  maybe not

Step-by-step explanation:

Consider a couple of scenarios for a $20,000 car purchase and a $2000 rebate, with sales tax at 10%.

1) The rebate is applied directly to the purchase price.

  Taxable amount: $20,000 -2,000 = $18,000.

  Price with tax: $18,000 × 1.10 = $19,800

  Amount financed: $19,800.

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2) The rebate is given after the sale is complete.

  Taxable amount: $20,000

  Price with tax: $20,000 × 1.10 = $22,000

  Amount financed: $22,000

  Remaining loan balance if $2000 rebate is immediately applied to the loan: $22,000 -$2000 = $20,000

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If the loan is for 5 years at 3%, the payments and total costs are ...

  Scenario 1: Monthly payment $355.78;

     total cost of loan: 60×355.78 = 21,346.80

  Scenario 2: Monthly payment $395.31;

     total cost of loan: 55×395.31 = $21,742.05  (note there are fewer payments because of the initial payment to principal of $2000)

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Ted effectively has to finance an additional $200, equal to the sales tax on the rebate. So the delayed rebate costs him an extra $395.25 over the life of the loan.

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We have assumed certain tax and payment scenarios. If tax is not an issue, and if the loan terms are such that the rebate can be applied immediately to the loan amount, then <em>there may be no difference in total cost</em>, or the delayed rebate may result in a <em>lower</em> total cost due to the higher monthly payment.

7 0
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Can anyone help with this question
WARRIOR [948]

Answer:

a

Step-by-step explanation:

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7 0
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Point T is at (-3, 8). What are the coordinates of T' after R(y-axis) o R(x-axis)?
Whitepunk [10]

Given:

Point is T(-3,8).

To find:

The coordinates of T' after R(y-axis)\circ R(x-axis).

Solution:

We know that, R(y-axis)\circ R(x-axis) means the figure reflected across the x-axis then reflected across y-axis.

If a figure reflected across x-axis, then

(x,y)\to (x,-y)

T(-3,8)\to T_1(-3,-8)

If a figure reflected across y-axis, then

(x,y)\to (-x,y)

T_1(-3,-8)\to T'(-(-3),-8)

T_1(-3,-8)\to T'(3,-8)

Therefore, the required point is T'(3,-8).

4 0
3 years ago
If you wanted to make the graph of y = 8x - 10 less steep, as well as shift the
azamat

Answer:

4x-15=y

Step-by-step explanation:

The higher the rise over the run the more steep your slope will be thus 4x is less steep than 8x because it does not rise as much.

The y intercept shifted downward means anything (-10>b) can be plausible for b.

3 0
3 years ago
the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const
laiz [17]
In general, the volume

V=\pi r^2h

has total derivative

\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)

If the cylinder's height is kept constant, then \dfrac{\mathrm dh}{\mathrm dt}=0 and we have

\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}

which is to say, \dfrac{\mathrm dV}{\mathrm dt} and \dfrac{\mathrm dr}{\mathrm dt} are directly proportional by a factor equivalent to the lateral surface area of the cylinder (2\pi r h).

Meanwhile, if the cylinder's radius is kept fixed, then

\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}

since \dfrac{\mathrm dr}{\mathrm dt}=0. In other words, \dfrac{\mathrm dV}{\mathrm dt} and \dfrac{\mathrm dh}{\mathrm dt} are directly proportional by a factor of the surface area of the cylinder's circular face (\pi r^2).

Finally, the general case (r and h not constant), you can see from the total derivative that \dfrac{\mathrm dV}{\mathrm dt} is affected by both \dfrac{\mathrm dh}{\mathrm dt} and \dfrac{\mathrm dr}{\mathrm dt} in combination.
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