Answer:
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Answer:
Molarity NaOH = 0.85M (2 sig figs)
Explanation:
48.0ml(0.220M H₂SO₄) + 25ml(Xmolar NaOH)H₂SO₄ + 2NaOH => Na₂SO₄ + 2H₂O
2(molarity x volume) H₂SO₄ = (molarity x volume) NaOH
2(0.220M x 48.0ml) = 25.0ml x Molarity NaOH
Molarity NaOH = 2(0.220M x 48.0ml)/25.0ml = 0.8448M ≅ 0.85M (2 sig figs)
Answer:
1) Assuming you mean Phosphorous Pentoxide (P4O10) there are 6.02x10^23 x 4 (number of P in P4O10) x 5 moles = 1.38x10^25
2) Divide 1.0x10^20/6.02x10^23 = 1.7x10^-4 moles
3) The balanced equation would be 4P + 5O2 —-> P4O10. Starting with 8 moles of P 8/4 = 2. You generate 2 moles P4O10
4) CH4 has a molecular mass of 12+4 = 16. Starting with 100g/16g/mole = you have 6.25 moles of methane. As there are 4 atoms of hydrogen in each molecule of methane, you multiply 6.25 moles methane by 4 atoms H/molecule and get 25 moles of hydrogen or 1.505e25 atoms of hydrogen
Explanation:
Answer:
Explanation:
Halogens are elements in group 17 or 7 in the periodic table.
Iodine is a halogen.