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Zepler [3.9K]
3 years ago
7

After adding 20.0 mL of 5% NaOH solution into the remaining organic layer, followed by mixing and venting, the solution separate

d into two distinct layers. Match the following:
1. The top layer was the ______________ layer.
2. 9-fluorenone was most soluble in the ____________ layer.
3. Deprotonated chloroanilic acid was most soluble in the _____________ layer.
4. The bottom layer was the __________________ layer.
5. The organic layer was a ________________ colored solution.
6. The aqueous layer turned into a _____________ colored solution.
a. organic
b. aqueous
c. yellow
d. pink
Chemistry
1 answer:
Arisa [49]3 years ago
7 0

Answer:

Explanation:

The objective of this experiment is to match the expected result with each of the propositions given after the experiment had been carried out.

1. The top layer was the <u>organic </u> layer. This is because all the organic compounds have lesser density than water except chloroform that will be formed when NaOH is added.

2. 9-fluorenone was most soluble in the <u>organic </u>layer. This is so as a result of its non-polar carbon structure.

3. Deprotonated chloroanilic acid was most soluble in the <u>aqueous </u>layer as a result of the formation of an electrovalent bond with water.

4. The bottom layer was the <u>aqueous </u>layer as a result of the huge amount of water density.

5. The organic layer was a <u>yellow</u> colored solution.

6. The aqueous layer turned into a <u>pink</u><u> </u> colored solution.

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volume is the amount of space something occupies

Explanation:

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Choose the molecule or compound that exhibits dipole-dipole forces as its strongest intermolecular force. a) BCl3 b) N2 c) H2 d)
Nana76 [90]

Answer:

SO₂

Explanation:

The dipole-dipole force is not only determined by the electron density around each atoms in the molecule (dependent of electronegativity difference), but also how the atoms in the molecules are arranged. In general, the more symmetric a molecule is, the less dipole force it exerts as each dipole moments cancels each other out.

Now let's examine each answer

  • b and c, N₂ and H₂ are composed of same type of atoms, therefore, no dipole moment occurs, and no dipole-dipole forces are exerted
  • a and e, BCl₃ and CBr₄ are composed of atoms with different electronegativity, but are symmetric. With BCl₃ having trigonal planar structure and CBr₄ has tetragonal structure, each B-Cl and C- Br bond cancels out each other dipole moment, and thus, no dipole moments were generated.
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3 years ago
Consider a transition of the electron in the hydrogen atom from n=3 to n=7.
kow [346]

<u>Answer:</u>

<u>For a:</u> The wavelength of light is 1.005\times 10^{-6}m

<u>For b:</u> The light is getting absorbed

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 3

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{7^2} \right )\\\\\lambda =1.005\times 10^{-6}m

Hence, the wavelength of light is 1.005\times 10^{-6}m

  • <u>For b:</u>

There are two ways in which electrons can transition between energy levels:

  1. <u>Absorption spectra:</u> This type of spectra is seen when an electron jumps from lower energy level to higher energy level. In this process, energy is absorbed.
  2. <u>Emission spectra:</u> This type of spectra is seen when an electron jumps from higher energy level to lower energy level. In this process, energy is released in the form of photons.

As, the electron jumps from lower energy level to higher energy level. The wavelength is getting absorbed.

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4 years ago
Balance this chemical equation <br><br>Ca(OH)2 + HCl ---&gt; CaCl2 + H2O​
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Answer:

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Ca(OH)2(s) + <u>2</u>HCl(aq) ---> CaCl2(aq) +<u>2</u>H2O​ (l) (balanced equation)

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Alex_Xolod [135]
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\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}

\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles

7 0
2 years ago
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