Question

Please help!!!

Answer 1

Answer:

         $\large\boxed{\large\boxed{1M}}$

Explanation:

1. Reaction

  $H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

2. Mole ratio

    $\dfrac{2molKOH}{1molH_2SO_4}$

3. Sulfuric acid

     $Molarity=\dfrac{moles}{volume(liters)}$

     $Moles=Molarity\times Volume(liters)$

     $Moles=0.20M\times 0.017liter=0.034molH_2SO_4$

4. Potassium hydroxide

    $\dfrac{2molKOH}{1molH_2SO_4}\times 0.034molH_2SO_4=0.068molKOH$

    $Molarity=\dfrac{0.068mol}{0.06liter}=1.13M\approx 1M$