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Delicious77 [7]
4 years ago
12

For a summer job, you work for a pool resurfacing business. you’ve finished resurfacing the pool and it is now time to fill the

empty pool with water. there are 2 water hoses that you can use to refill the pool. you wonder how long it is going to take to fill the pool because you have plans with friends and you need to leave by 6:15 PM. You decide to time the water flow of hoses as it fills a 5 gallon bucket. the first hose can fill the bucket in 4 seconds while the second hose can fill the same in 36 seconds. the pool needs 20,000 gallons of water.
a. How long will it take fill the pool with the first hose? It is now 2PM, will you be able to leave by 6:15pm?
b. You get the idea both hoses to fill the pool and hopefully fill up the pool faster. Will using both hoses be enough to fill up the pool in time for you to leave at 6:15PM?
Mathematics
1 answer:
ruslelena [56]4 years ago
7 0

Answer:

a. 267 hrs b.

Step-by-step explanation:

a.)4 secs divided by 5 gals is .8 secs per gal, multiply by 20,000 gals, is 16,000 secs, divide that by 60 secs in an hour and you get 266.666 hrs

b.)42 hrs with both hoses

.8 secs per gal and 7.2 secs per gal = 8 secs per gal

20,000 = 8 gals per hour = 2500 secs  divided by 60 secs per hour = 41.66

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SOLVE 10 PLEASE HELP ME I AM VERY CONFUSED. THIS IS DUE IN 10 MINUTES. WILL MARK AS BRAINIEST ANSWER IF CORRECT
Nimfa-mama [501]
Solution for both: (-2,2)
solution for equation one: (0,8)
solution for equation two: (0,6)
8 0
3 years ago
What is <br>2/3 of 1/4 of x = 1360​
Murljashka [212]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 8160}}}}}

Step-by-step explanation:

\sf{ \frac{2}{3}  \times  \frac{1}{4}  \times x = 1360}

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term

\longrightarrow{ \sf{ \frac{2 \times 1}{3 \times 4}  \times x = 1360}}

\longrightarrow{ \sf{ \frac{2}{12}  \times x = 1360}}

\longrightarrow{ \sf{ \frac{1}{6} x = 1360}}

Solve for x

\longrightarrow{ \sf{x = 1360 \times 6}}

\longrightarrow{ \sf{x = 8160}}

Hope I helped!

Best regards! :D

5 0
3 years ago
jonah is planting a rectangular garden the perimeter of the garden is 120 yards and the width is 20 yards what is the length of
Paul [167]
The length would be:

120-2(20)=2x

Then you would solve for x.

120-40=2x
80=2x

x=40, so the length is 40 yards.
7 0
4 years ago
A sample of 25 commuters in the Washington, D.C., area yielded the sample mean commute time of 27.97 minutes and sample standard
xxMikexx [17]

Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes. The interpretation is that we are 99% sure that the true mean ommute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{10.04}{\sqrt{25}} = 5.1706

The lower end of the interval is the mean subtracted by M. So it is 27.97 - 5.1706 = 22.7994 minutes

The upper end of the interval is the mean added to M. So it is 6.4 + 0.3944 = 33.1406 minutes.

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes. The interpretation is that we are 99% sure that the true mean ommute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes.

5 0
4 years ago
Classify the triangle based on the side lengths 10, 12 and 23.
liberstina [14]

Answer:

Scalene.

as all side lengths are different.

8 0
3 years ago
Read 2 more answers
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