Let the three numbers be x, y, and z.
If the sum of the three numbers is 3, then x+y+z=3
If subtracting the second number from the sum of the first and third numbers gives 9, then x+z-y=9
If subtracting the third number from the sum of the first and second numbers gives -5, then x+y-z=-5
This forms the system of equations:
[1] x+y+z=3
[2] x-y+z=9
[3] x+y-z=-5
First, to find y, let's take do [1]-[2]:
x+y+z=3
-x+y-z=-9
2y=-6
y=-3
Then, to find z, let's do [1]-[3]:
x+y+z=3
-x+-y+z=5
2z=8
z=4
Now that you have y and z, plug them into [1] to find x:
x+y+z=3
x-3+4=3
x=2
So the three numbers are 2,-3, and 4.
The answer is c, 2.To find this, look on the graph for a point with the y value of -1. (2,-1) is the solution.
For angle a it will be 42degrees and for angle b it will be 138degrees and i am 100%sure
You have 50 ways because if there are 10 different types of prizes with 5 prizes you can just multiply that to get your different ways to select the prizes.
<span>A) How many cups of flour are there per serving?
</span>1 ½ cups of flour --------<span>6 servings
? cups of flour ------- 1 serving
</span>1 ½
------------
6
= 3/2 x 1/6
= 1/4
answer: 1/4 cups of flour per serving
<span>B) how many total cups of sugar(white and brown) are there per serving?
</span>total white and brown: <span>2/3 + 1/3 = 3/3 = 1 cups (combine)
1 cup of sugar (white and brown) </span>--------6 servings
? cups of sugar (white and brown) ------ 1 serving
1
----- = 1/6
6
answer: 1/6 cups of sugar (white and brown) per serving
<span> (c) Suppose you modify the recipe so that it makes 9 servings. How much more flour do you need for the modified recipe than you need for the original recipe?
</span>
3/2 cups of flour --------6 servings
? cups of flour -----------9 servings
9 * 3/2
-----------
6
= (13 1/2) / 6
= 2 1/4
2 1/4 ( 9 servings) - 1 1/2(6 servings) = 3/4 cups
answer: you need 3/4 more cups of flour
