Answer:
15 seconds.
Step-by-step explanation:
∵ The distance covered by plane in first second = 100 ft,
Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,
So, distance covered in second second = 200,
In third second = 300,
In fourth second = 400,
............, so on....
Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds
( Sum of AP )
Suppose the distance covered in n seconds is 12,000 feet,
∵ n can not be negative,
Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.
Use PEMDAS method to execute operations in the following order:
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
First equation:
12 + (38 - 18)2 = 12 + 20 × 2 = 52
Second equation:
(12)2 - 6(2 - 23) = 24 - 6(-21) = 24 + 126 = 150
Hope this helps.
Answer:
y = (x + 6)² - 1
Step-by-step explanation:
So there are two ways of doing it, completing the square or partial factoring (which is what i prefer and will show)
so we will get x first:
x^2+12x
We are factoring x
x(x+12)
Now you do x=-12/2
x=-6
Now that you have x, you plg that back into the equation to get y
y= -6^2 +12(-6) +35
= 36-36+35
=-1
Put into vertex form
y = (x + 6)² - 1
We have cos( x - y ) = cosxcoy + sinxsiny <=> cos ( π - x ) = cosπcosx + sinπsinx <=> cos ( π - x ) = (-1)cosx + 0sinx = -cosx;
Statement 3:
NO and ON are the same line. They are congruent by the reflexive property (a line segment is a reflection of itself).
Statement 4:
Shape MNO and shape PON are congruent by side-side-side since:
side PN = side MO
side MN = side PO
side NO = side ON
Answer: Fourth option
