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3 years ago

12

Dustin had five outstanding checks that totaled $117.54. What should his check register balance be if he had an ending balance o

f $599.43 and outstanding deposits that totaled $235.14?

1 answer:

Olenka [21]3 years ago

4 0

You would add $599.43 and $235.14 then subtract $117.54 so youd get $717.03

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A machine with a cost of $61,800 has an estimated residual value of $4,986 and an estimated life of 5 years or 18,970 hours. Wha

Leto [7]

Answer:

$14,832

Explanation:

Depreciation charge = 2 x SLDP x BVSLDP

where,

SLDP = 100 ÷ useful life = 20 %

and

BVSLDP = Cost or Net Book Value

therefore,

1st year

Depreciation charge = 2 x 20 % x $61,800 = $24,720

2nd year

Depreciation charge = 2 x 20 % x ($61,800 - $24,720) = $14,832

conclusion

the amount of depreciation for the second full year is $14,832

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3 years ago

Wild Trails Inc., an adventure resort in Texas, has 500 shares of outstanding common stock and has not issued any preferred stoc

erma4kov [3.2K]

Answer:

$55

Explanation:

The earnings per share indicate the profit per outstanding stocks and it is calculated by dividing the net income by the number of shares of outstanding stocks. According to this,

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4 years ago

If a family spends its entire budget in a given time frame, the family can afford either 85 cans of vegetables or 45 frozen pizz

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Answer: 0.52

Explanation:

Opportunity cost is the benefit that is obtained from a good or from an activity is foregone by choosing some other alternative.

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3 years ago

A concrete and rock crusher for demolition work has been purchased for $50,000, and it has an estimated SV of $10,000 at the

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Answer:

Instructions are listed below.

Explanation:

Giving the following information:

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Annual depreciation= [(original cost - salvage value)/useful life of production in units]*units produced

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3 years ago

In an Argand diagram, the point P represents the complex number z, where z = x + iy. Given that z + 2 = λi(z + 8), where λ is a

Scilla [17]

Answer:

The answer is " $\boxed{z= \frac{-16}{5}- \frac{-12}{15}i}$ ".

Explanation:

As the problem stands

At the point of P, it is the complex number z in the Diagram of Argand and z = X+iy.

We have said this: $(z+2)= \lambda i (z +8) .... (i)$

where the $\lambda$ parameter is a true

The conceptual equation of the locus P varies between $z = x+iy \ \ \ to \ \ \ \lambda$

And in equation mentioned above.

$x+iy+2=\lambda i(x+iy+8) \\\\x+iy+2= \lambda xi+ \lambda i^2y+\lambda 8i\\\\ x+2+iy=-y \lambda +i(x+8)\lambda\\\ compare \ real \ and \ imaginary\ part \\\\\ x+2 = -y\lambda \\\\y= (x+8) \lambda\\\\ \lambda = \frac{x+2}{-y} \\ \\ \lambda = \frac{y}{x+8}$

$y^2= -x^2-10x-16 ....(ii)\\\\z= \mu (4+3i)....(iii)\\\\\ z= x+iy \\\\x+iy = 4\mu + 3 \mu i \\\\x= 4\mu \\\\y= 3\mu$

put the value of x, y in equation (ii) we get:

$5\mu +4=0\\\\\mu = \frac{-4}{5} \\\\$

to put the of $\mu$ in equation (iii) we get:

$z= \frac{-4}{5} (4+3i) \\\\ \boxed{z= \frac{-16}{5}- \frac{-12}{15}i} \\$

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4 years ago