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Vesna [10]
3 years ago
10

Determine the possible values of the given random variable and indicate as your answer whether the random variable is finite dis

crete, infinite discrete, or continuous. A 12-sided die is tossed 1020 times. Let the random variable X be the number of times that the 12-sided die shows 8 dots.
A) What are the possible values of X?

S = {X | X ≥ 0} ....S = {0, 1, 2, ... } .... none of these.....S = {X | 0 ≤ X ≤ 1020}.....S = {0, 1, 2, ... 1020}


B) Classify X.

infinite discrete random variable ... finite discrete random variable ...... continuous random variable.
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

A) S={0,1,2,...,1020}

B) X is a finite discrete random variable.

Step-by-step explanation:

A) What are the possible values of X?

Since the die is tossed 1020 times, it can show 8 dots 0, 1, 2,...or 1020 times. Hence, the possible values of X are

S={0,1,2,...,1020}

B) Classify X as infinite discrete random variable, finite discrete random variable, continuous random variable.

Since X can only have a finite number of outcomes (the number of elements in S), X is a finite discrete random variable.

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Answer:

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Step-by-step explanation:

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According to SOH CAH TOA

Sin theta = opposite/hypotenuse = 8/3

Opposite = 8

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adj² = hyp² - opp²

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adj² = 9-64

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3 years ago
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My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

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there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

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It tells us that the trip there is with the wind and the trip back is against the wind:

           

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back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

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there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

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Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

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