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3 years ago

PLEASE HELP GUYS THANK YOU IN ADVANCED

Mathematics

2 answers:

VikaD [51]3 years ago

6 0

Answer:

x=3.5

Step-by-step explanation:

lawyer [7]3 years ago

3 0

Answer:

x=sqrt(12) or 2sqrt(3)

Step-by-step explanation:

You can just use pythagorean theorem for this.

We can do 4^2+x^2=8^2

This gives us 16+x^2=64.

Simplify: x^2=48

x=sqrt(48)

Now, we can find x!

We just have to do 6^2+x^2=sqrt(48).

We get 36+x^2=48

simplify: x^2=12

Now, x=sqrt(12) or 2sqrt(3)

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2 years ago

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Step-by-step explanation:

Your answer is correct! When you multiply 2 matrices, the inner dimensions have to be equal. If they are equal, the resulting dimensions would be the outer dimentions.

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3 years ago

A one-parameter family of solutions of the de p' = p(1 − p) is given below.

tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

$c_{1} = -\frac{4}{3}$

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

So there is not a solution curve passing through the point(0,1).

3 0

3 years ago