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3 years ago

What's the exact value of tan 15°?

Mathematics

1 answer:

marusya05 [52]3 years ago

3 0

Answer:

The answer is 0.267949192

Step-by-step explanation:

I hope that is enough numbers.

You might be interested in

Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has

Feliz [49]

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = $\frac{1}{4}x$

Sweets given to Raji = 5

Remaining sweets = 7

$x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16$

6 0

2 years ago

WILL MARK BRAINLEIST

yaroslaw [1]

Answer:

Which one do we have to answer?

Step-by-step explanation:

First of all, I can't even see the whole question. Second of all, you didn't tell us what to answer. Please comment on this answer on which question you need help with.

8 0

3 years ago

Read 2 more answers

Foot pieces you can cut from 5 feet of

Rzqust [24]

Answer:

1p = r

Step-by-step explanation:

You are asking how many 1-foot pieces you can make out of a 5 foot piece of ribbon. You are asking for an equation.

p = the # of pieces

r = the amount of ribbon

So lets try the equation:

1p = r

1(4) = r

1*4 = 4

4 = r

<h2>PLEASE MARK BRAINLIEST! </h2>

7 0

3 years ago

What is the rate of change ? y=-5x-3

KatRina [158]

Answer:

the rate of change is -5.

Step-by-step explanation:

y = -5x - 3

-5 = rate of change

-3 = x intercept

6 0

2 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago