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Leno4ka [110]
3 years ago
5

How do i solve for X 2x+4-7x+9x= -2 What is X?

Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

x = -3/2  or  -1.5

Step-by-step explanation:

You have to get X on one side by itself.

2x + 4 - 7x + 9x = -2

Subtract the 4

2x - 7x + 9x = -6

Combine like terms

-5x + 9x = -6

Combine like terms

4x = -6

Divide by 4

x = -6/4

Simplify

x = -3/2  or  -1.5

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mojhsa [17]

Answer:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

Step-by-step explanation:

Given

(\frac{6}{10})^3 * (\frac{5}{9})^2

Required

Solve:

(\frac{6}{10})^3 * (\frac{5}{9})^2

Simplify 6/10

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2

Express 9 as 3^2

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Apply law of indices

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}

Express as a sing;e fraction

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}

Apply law of indices:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

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r-ruslan [8.4K]
When you're talking about equations, 'literal' means 'has letters in it'. 'C' is the only one with any letters in it.
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