Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
Step-by-step explanation:
I think both are the same because you have equations in the formula and what ever you do on one side you do to the other.
Answer:
y = 5/2x - 7
Step-by-step explanation:
5x - 2y = 4
5x - 4 = 2y
y = 5/2x - 2
Slope = 5/2
Point (2,-2)
y-intercept: -2 - (5/2)(2) = -2 - 5
= -7
Answer:
0
Step-by-step explanation:
all real numbers are solutions
Answer: Choice A) {-4, -1, 3, 5, 6}
The domain of a relation is the set of possible x inputs. All we do is list the x coordinates of the given points. The order doesn't matter but your book has decided to list the x values from smallest to largest.
Side note: the list of possible output y values is known as the range.