2 years ago

Lisa drank 4/5

Mathematics

1 answer:

vesna_86 [32]2 years ago

5 0

Answer:

12/15 + 10/15= 1 whole and 7/15

Step-by-step explanation:

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You are tiling a 1 square metre bathroom with 10cm square tiles. The exact number of the tiles needed is yet unknown because you

belka [17]

We cannot determine the cost of the tiles from the given information, so the question cannot be answered.

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2 years ago

Find 4 consecutive intergers such that the sum of the secound and forth is 34

ankoles [38]

Consecutive integers are 1 aparrt
they are
x,x+1,x+2,x+3

the 2nd and 4th sum is x+1 and x+3
sum is 34
x+1+x+3=34
2x+4=34
minus 4
2x=30
divide 2
x=15

x+1=16
x+2=17
x+3=18

the numbers are 15,16,17,18

4 0

3 years ago

SOMEONE PLEASE HELP ME PLEASE!!!

tankabanditka [31]

Answer:

193%

Step-by-step explanation:

40.2 - 13.7 = 26.5

26.5 ÷ 13.7 = 1.93

1.93 = 193%

7 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$