Answer:
change in height is 1.664 mm
Explanation:
Given data
drops = 3.00 mm
diameter = 5.00 cm = 0.05 mm
decrease = 350 cm^3
temperature = 95°C to 44.0°C
to find out
the decrease in millimeters in level
solution
we will calculate here change in volume so we can find how much level is decrease
change in volume = β v change in temp ...............1
here change in volume = area× height
so = /4 × d² h
so we can say change in volume = /4 × d² × change in height .......2
so from equation 1 and 2 we calculate change in height
( β(w) -β(g) )× v× change in temp = /4 × d² × change in height
change in height = 4 × ( β(w) -β(g) ) v× change in temp / /4 × d²
put all value here
change in height = 4 × ( 210 - 27 )(350 ) × (95-44) / /4 × 0.05²
change in height is 1.664 mm
<h2>
The speed of the rock just before it reaches the water 25.0 m below the point where the rock left your hand is 45.06 m/s</h2>
Explanation:
First let us find the initial velocity,
We have after 8 seconds the displacement is zero,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = ?
Acceleration, a = -9.81 m/s²
Time, t = 8 s
Displacement,s = 0 m
Substituting
s = ut + 0.5 at²
0 = u x 8 + 0.5 x -9.81 x 8²
u = 39.24 m/s
Initial velocity is 39.24 m/s.
Now this case is similar to case where a rock is thrown at 39.24 m/s downward.
We have equation of motion v² = u² + 2as
Initial velocity, u = 39.24 m/s
Acceleration, a = 9.81 m/s²
Final velocity, v = ?
Displacement, s = 25 m
Substituting
v² = u² + 2as
v² = 39.24² + 2 x 9.81 x 25
v = 45.06 m/s
The speed of the rock just before it reaches the water 25.0 m below the point where the rock left your hand is 45.06 m/s
Answer:
Explanation:
Given:
- mass of aluminium,
- initial temperature of the aluminium cylinder,
- mass of coffee,
- initial temperature of coffee,
- specific heat of coffee (assuming water),
- specific heat of aluminium,
When the coffee and the aluminium cylinder come in contact then heat released by the coffee is equal to the heat gained by the aluminium.
<u>Mathematically:</u>
is the final temperature of agreement.