- Mass of the car (m) = 2000 Kg
- Initial velocity (u) = 15 m/s
- Force (F) = 10000 N
- Time (t) = 3 s
- Let the acceleration be a.
- By using the formula, F = ma, we get,
- 10000 N = 2000 Kg × a
- or, a = 10000 N ÷ 2000 Kg
- or, a = 5 m/s^2
- Let the final velocity be v.
- By using the formula, v = u + at, we get,
- v = 15 m/s + 5 m/s^2 × 3 s
- or, v = 15 m/s + 15 m/s
- or, v = 30 m/s
<u>Answer</u><u>:</u>
<em><u>The </u></em><em><u>new </u></em><em><u>sp</u></em><em><u>e</u></em><em><u>ed </u></em><em><u>of </u></em><em><u>the </u></em><em><u>car </u></em><em><u>is </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
Je ne Sachez que Qu’est-ce que le
Answer:
Gravity
Explanation:
Gravity is a force that pulls the surface of the earth and keeps the planets in orbits around the sun.
Answer:
Mass = 386 kg
Explanation:
<u><em>Density = Mass / Volume</em></u>
Mass = Density × Volume
Where D = 19300 kg/m³ , V = 0.02 m³
<em>Putting the given in the above formula</em>
Mass = 19300 × 0.02
Mass = 386 kg
Answer:
26.9 Pa
Explanation:
We can answer this question by using the continuity equation, which states that the volume flow rate of a fluid in a pipe must be constant; mathematically:
(1)
where
is the cross-sectional area of the 1st section of the pipe
is the cross-sectional area of the 2nd section of the pipe
is the velocity of the 1st section of the pipe
is the velocity of the 2nd section of the pipe
In this problem we have:
is the velocity of blood in the 1st section
The diameter of the 2nd section is 74% of that of the 1st section, so
The cross-sectional area is proportional to the square of the diameter, so:
And solving eq.(1) for v2, we find the final velocity:
Now we can use Bernoulli's equation to find the pressure drop:
where
is the blood density
are the initial and final pressure
So the pressure drop is: