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Dahasolnce [82]
3 years ago
11

The answer May someone please help me out.

Physics
2 answers:
Olin [163]3 years ago
7 0

magnesium is an element

Andru [333]3 years ago
7 0

It looks like you've already marked the last choice ... 'element'.  If you did, then don't change it.  It's correct.  Anything you find listed on the periodic table is an element.

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An unknown substance has a mass of 670 kg and a volume of 782 m^3. Will it float in water? (Water has a density of 1,000 kg/m^3.
matrenka [14]

Answer:

It will float

Explanation:

its density is lower than density of water

Its density is 670 / 782 = 0.856 kg/m³

6 0
3 years ago
A rebuttal that Rousseau would use to counter the King’s argument?
ankoles [38]

Is this your Question:

Read the hypothetical situation below and answer the question that follows.

In response to criticisms that the King of Mordor has failed to gain the consent of his people, the King claims that he does in fact represent the consent of the people because without their King, society would crumble into chaos.

Which statement BEST represents a rebuttal that Rousseau would use to counter the King's argument?

A. Absolute chaos is preferable to the absolute power of the King.

B. The King of Mordor should establish a system of checks and balances.

C. If the King of Mordor were to represent the will of his people, then he would at least provide the public services demanded by his people.

D. It is impossible for the King of Mordor to have the consent of the people because the monarchy is not a freely formed government in which the people have a say in how it operates.

If this is your question.. Here is your Answer:

Answer:  D. It is impossible for the King of Mordor to have the consent of the people because the monarchy is not a freely formed government in which the people have a say in how it operates.

Explanation:

Rousseau believed that sovereignty (the power to make laws) belonged to the people, not one person, and that it should be carried out by a representative body of the people who are elected by them on their behalf. While he agreed society requires a ruler(s), he thinks they should be chosen by the people.  

5 0
3 years ago
A 2.0 kg block on a horizontal frictionless surface is attached to a spring whose force constant is 590 N/m. The block is pulled
SVETLANKA909090 [29]

Answer:

The  value is  v =  -0.04 \  m/s

Explanation:

From the question we are told that

   The  mass  of the block is  m  =  2.0 \ kg

   The  force constant  of the spring is  k  =  590 \ N/m

   The amplitude  is  A =  + 0.080

   The  time consider is  t =  0.10 \  s

Generally the angular velocity of this  block is mathematically represented as

      w =  \sqrt{\frac{k}{m} }

=>   w =  \sqrt{\frac{590}{2} }

=>   w = 17.18 \  rad/s

Given that the block undergoes simple harmonic motion the velocity is mathematically represented as  

         v  =  -A w sin (w* t )

=>       v  = -0.080 * 17.18 sin (17.18* 0.10 )

=>       v =  -0.04 \  m/s

7 0
4 years ago
Water having a density of 1000 kg/m^3 is flowing with a velocity of 3 m/s through a round pipe. There is a restriction within th
Fofino [41]

Answer:

12 m/s

Explanation:

Using the continuity equation, which is an extension of the conservation of mass law

ρ₁A₁v₁ = ρ₂A₂v₂

where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.

ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow

A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)

A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)

v₁ = velocity of the fluid flowing at point 1 = 3 m/s

v₂ = velocity of the fluid flowing at The restriction = ?

ρ₁A₁v₁ = ρ₂A₂v₂

Becomes

A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)

(πD₁²/4) × 3 = (πD₂²/4) × v₂

3D₁² = D₂² × v₂

But

D₂ = (D₁/2)

And D₂² = (D₁²/4)

3D₁² = D₂² × v₂

3D₁² = (D₁²/4) × v₂

(D₁²/4) × v₂ = 3D₁²

v₂ = 4×3 = 12 m/s

8 0
4 years ago
The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the10-g bullet is traveling at 300m/swhe
WARRIOR [948]

Answer:

6.8 mm

Explanation:

We are given that

Mass of block,m=10 kg

Mass of bullet,m_b=10 g=10\times 10^{-3} kg

1 kg=1000 g

Total mass of system,M=m+m_a=10+10\times 10^{-3}=10.01kg

Speed of bullet,u=300 m/s

\theta=30^{\circ}

By law of conservation of momentum

m_bucos\theta=Mv

v=\frac{m_bvcos\theta}{M}=\frac{0.01\times 300cos30^{\circ}}{10.01}=0.259m/s

According to law of conservation of energy

Change in kinetic energy of system=Change in potential energy of system

\frac{1}{2}Mv^2-0=Mgh-0

\frac{1}{2}(10.01)(0.259)^2=10.01\times 9.8 h

Where g=9.8 m/s^2

h=\frac{(0.259)^2}{2\times 9.8}=0.0034m

1m=100 cm

h=0.0034\times 100=0.34 cm

Distance traveled by block=d=\frac{h}{sin\theta}=\frac{0.34}{sin30^{\circ}}=0.68 cm=6.8 mm

1cm=10 mm

4 0
4 years ago
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