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erik [133]
3 years ago
7

The inner and outer surface temperature of a glass window 10 mm thick are 25 and 5 degree-C, respectively. What is the heat loss

through a 1 m x 3 m window
Physics
1 answer:
miss Akunina [59]3 years ago
5 0

Answer:

The  heat loss is  H  =  8400\  W

Explanation:

From the question we are told that

   The thickness is  t = 10 \ mm = 0.01 \ m

    The inner temperature is  T_i =  25 ^oC

    The outer temperature is T_o  =  5 ^oC

    The length of the window is  L  = 1 m  

    The  width of the window is  w  =  3 m  

Generally the heat loss is mathematically represented as

      H  =  \frac{k  *  A *  \Delta  T}{t}

Where  k is the thermal conductivity of glass with value k  =  1.4\ W/m \cdot  K

   and A  is the area of the window with value

           A =  1 * 3

            A = 3 \  m^2

substituting values

       H  =  \frac{1.4 *  3 * (23-5)}{0.01}

       H  =  8400\  W

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The characteristics that follow are characteristics of two of Galileo's surviving double-convex lenses. The numbers given are ma
forsale [732]

Answer:

Explanation:

L 1: front radius 950 mm, rear radius 2700 mm, refractive index 1.528;

We shall use lens maker's formula , that is

1/f = (μ-1) ( 1/R₁ - 1/R₂) , μ is refractive index of the lens , R₁ and R₂ are  radius of curvature of front and rear curved surface.

1/f₁ = (1.528-1)( 1/950 + 1/2700)

f₁ = 1331 mm

L2: front radius 535 mm, rear radius 500 mm, refractive index 1.550.

1/f₂ = (1.550-1)( 1/535 + 1/500)

f₂ = 470 mm

largest angular magnification possible

= f₁ /f₂

= 1331 / 470

= 2.83 ( approx )

Length between two lenses

=1331 +470

= 1801  mm

=  1.8 m Ans

6 0
3 years ago
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Lera25 [3.4K]

Answer:

I can help with the last question.

Explanation:

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6 0
3 years ago
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An object has a mass of 5 kg and a velocity of 20 m/s. What is the momentum of the object?(1 point)
kotegsom [21]

Answer:

option C is correct

Explanation:

given mass=5 kg  

velocity=20 m/s

momentum,P=m v

p=5*20=100 kg m/s

3 0
3 years ago
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what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​
Reil [10]

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

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F = 800* 0.2

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3 years ago
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Akimi4 [234]

Explanation:

As we know, resistance is the ratio of voltage used and current flowing through the circuit. So,

<h3>R = V/I</h3>

By error calculation

<h3>∆R/R = [(∆V/V)100] + [(∆I/I)100]</h3>

V = 100 ± 6% V

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