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NNADVOKAT [17]
3 years ago
11

a school has 7 school buses each bus can seat 48 students a total of 303 students get on the bus to go to the school Camp how ma

ny empty seats will there be on the buses
Mathematics
2 answers:
Ksivusya [100]3 years ago
7 0
There will be 33 empty seats 
melomori [17]3 years ago
7 0
43 by dividing 303 by 7

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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
How to find the length of the radius of circle O
Andrei [34K]
You would have to find Circumference
5 0
3 years ago
Where to locate the nonnegative abscissa, positive ordinate
Fofino [41]
The location to the nonegative abscissa, positive ordinate is in the Q1 it means it is in the fisrt quadrant as seen in the next image: http://www.mathnstuff.com/math/spoken/here/1words/q/q2.htm
Hope this helps
4 0
3 years ago
Doña Gertrudis recolecta en promedio 75 litros de leche de cabra por día y utiliza alrededor de 5 litros para hacer un kilogramo
Nimfa-mama [501]

Answer:

825 pesos a day on average

1 dozen weight = 2.4 kg

Step-by-step explanation:

In ENGLISH:

Doña Gertrudis collects on average 75 liters of goat milk per day and uses around 5 liters to make one kilogram of cheese. The cheeses he makes weigh 200 grams each and he sells them for 132 pesos a dozen. How much money do you get per day on average from the sale of your cheeses? How many kilograms does the dozen cheeses weigh?

<u>Solution:</u>

75 Liters / 5 Liters = 15

15 * 1 kg = 15 kg of cheese per day

15kg in grams is 15*1000 = 15,000 grams

Each cheese block is 200 grams, so number of blocks of cheese:

15,000/200 = 75 blocks of cheese

1 dozen (12) = 132 pesos, so 1 would be:

132/12 = 11 pesos PER BLOCK

SO, 75 blocks of cheese = 75 * 11 = <u>825 pesos (per day on average)</u>

<u></u>

Dozen cheese weight in kg,

200 grams * 12 = 2400 grams

In kg,

2400/1000 = <u>2.4 kg</u>

8 0
3 years ago
P and W are twice-differentiable functions with P(7)=2(W(7)). The line y=9+2.5(x-7) is tangent to the graph of P at x=7. The lin
fiasKO [112]

Using the product rule, we have

m(x) = x W(x) \implies m'(x) = xW'(x) + W(x)

so that

m'(7) = 7W'(7) + W(7)

The equation of the tangent line to <em>W(x)</em> at <em>x</em> = 7 has all the information we need to determine <em>m'</em> (7).

When <em>x</em> = 7, the tangent line intersects with the graph of <em>W(x)</em>, and

<em>y</em> = 4.5 + 2 (7 - 7)   ==>   <em>y</em> = 4.5

means that this intersection occurs at the point (7, 4.5), and this in turn means <em>W</em> (7) = 4.5.

The slope of this tangent line is 2, so <em>W'</em> (7) = 2.

Then

m'(7) = 7\cdot2 + 4.5 = \boxed{18.5}

4 0
3 years ago
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