Answer:
There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.
Step-by-step explanation:
With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:
- n=4 (the amount of batteries picked for the sample).
- p=3/10=0.3 (the proportion of dead batteries).
- k≥1 (the amount of dead batteries in the sample needed to not sell the package).
The probability of having k dead batteries in the sample is:

Then, the probability of having one or more dead batteries in the sample (k≥1) is:

Answer:
85
Step-by-step explanation:
Place the 9 in for X and 9 to the second power is 81. Then add 4...85.
Answer:
first find the area of the big rectangle = 12×14=168
area of the small unshaded rectangle =2×5×6=60
area of the shaded region = 168-60=108
Answer:
125 defective jeans
Step-by-step explanation:
We are told that;
During inspections, 5 defective pairs of jeans are found in a shipment of 200 pairs of jeans .
We are supposed to determine the number of defective jeans in a shipment of 5000 pairs, if the trend continues.
Therefore;
5 defective = 200 pairs
What about in 5000 pairs?
Number of defective pairs = (5000 × 5 ) ÷ 200
= 125 defective pairs
Thus, in a shipment of 5000 pairs of jeans there will be 125 defective pairs