All categories

3 years ago

(1+5^2)-16(1/2)^3 step by step of solving this

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

7 0

Power: 5 ^ 2 = 25

Add: 1 + 25 = 26

Power: 1

^ 3 = 13

= 1

Multiple: 16 * 1

= 16 · 1

1 · 8

= 16

= 2 · 8

1 · 8

= 2

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(16, 8) = 8

Subtract: 26 - 2 = 24

You might be interested in

How do you find the volume of a pyramid?

amm1812

By knowing the volume of a triangle and that the triangle has all equal sides

4 0

3 years ago

Read 2 more answers

Helpppppppppppppppppppppppp

coldgirl [10]

K is 'angle bisector' because it seperated the angle's center.
Hope it helps!
#MissionExam001

8 0

3 years ago

What is an equation of the line that passes through the point (3,-8) and has a slope of -2<br>

makvit [3.9K]

Answer:

y = -2x - 2

Step-by-step explanation:

Given:

m = -2

Slope-intercept:

y - y1 = m(x - x1)

y + 8 = -2(x - 3)

y + 8 = -2x + 6

y = -2x - 2

3 0

2 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

3 years ago

Read 2 more answers

Can someone please help me with number 2 thank you

liubo4ka [24]

1250 students last year

3 0

3 years ago

Read 2 more answers