Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ 
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Whisker plots is not that hard you just have to no the Quartiles
the center of the graph is Q2 the first dot to the left is the lower quartile the last dot to the left is upper quartile so the second dot is Q1 and the 4 dot is Q3
Dang that’s hard , hope somebody helps you.
.73 x .05= .0365
.733333333 x .0000000555555555= .036555555555
i think this is correct hope this helps
Answer:
Step-by-step explanation: